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Can A Fly Stop A Train?! (more Technical)


boon racoon

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imagine this callum:

you are wearing roller skates (or lollerskates if you so prefer).

you are standing on a treadmill (running machine?)

you set it to 5mph, step on, and hold on to the handle thing on the front.

you are now standing still, with the wheels of the roller/lollerskates turning quickly due to the treadmill.

imagine your arms are fully extended, while holding on to the handle thing.

you now fancy a drink, this physics stuff is demanding.

you pull on the handle, which moves you forwards on the treadmill, closer to your drink. this moves you forwards relative to the world around you. even if the treadmill sped up, it would not make it any harder for you to pull forwards to your drink.

oh and btw, you are the plane, your arms are the engines and the treadmill is the conveyor.

made sense?

if not, i tried.

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No, no, no, no no.

NO.

The plane isn't in the same position on the conveyor.

It's not moving at all, not even turned on, on the conveyor.

The conveyor moves it along.

Like if your were to stand still on a tread-mill.

If the conveyor went fast enough with the plane still on it, the plane will take off?

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i reccon the plane takes off for a second or less then falls back down. and repeats!

and as for the fly, flies can't travel fast enough surely :P and anyways if it was going at that speed it wouldnt stop the train it would smash tiny little holes right the way through it and out the other side, much like a bullet!

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The problem with the plane question is that the question is flawed. So there's no point discussing it becuase of that.

1+2x3 = 9

1+2x3 = 7

Both correct answers. (Y)

The plane will not take off, the plane will take off.

Both correct answers becuase the question isn't detailed enough.

QED.

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The problem with the plane question is that the question is flawed. So there's no point discussing it becuase of that.

1+2x3 = 9

1+2x3 = 7

Both correct answers. (Y)

The plane will not take off, the plane will take off.

Both correct answers becuase the question isn't detailed enough.

QED.

Nope incorrect. (with the mathsy bit)

BEDMAS

Brackets

Exponents

Division and Multiplication

Addition and Subtraction

Only the bottom ones right (1+2x3=7) because you do the multiplication before the addition. For the top one to be right it would have to be:

(1+2)x3=9

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Nope incorrect. (with the mathsy bit)

BEDMAS

Brackets

Exponents

Division and Multiplication

Addition and Subtraction

Only the bottom ones right (1+2x3=7) because you do the multiplication before the addition. For the top one to be right it would have to be:

(1+2)x3=9

Whey and curds someone witha brain! :P:) Quatro etra NOT demonstrata!

God at least in this thread a lot of people were arguing my case witth he plane thing.

I can't see why it is so difficult! Would a hovercraft instead of a plane be able to move forward on the conveyor? Yes? Well what if it lowered some little tiny jet engine wheels from the side? What f**kin difference would it make hahaha!? They would just spin!

Here's one:

When I look into a mirror, in the image i see, my right hand is my left hand and my left hand is my right hand. But my top is still the top of me and the bottom is still the bottom of me. Why am I flipped horizontally but not vertically? :turned:

Edited by Extreme_biker0
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Because your mirror is on upside down? My mirror flips both upsidedown and left-to-right, like it should do. Anyone who thinks otherwise is clearly a moron who did dual award science.

And the people that think the plane will take off don't need to be so aggressive about it. Especially seeing as we don't even have the exact wording of the problem which is crucial. But then what do I know, I only did dual award science GCSE :lol:

P.S. This is a whole new can of worms:

The Monty Hall Problem

Suppose you're on a game show, and you're given the choice of three doors. Behind one door is a car, behind the others, goats. You pick a door, say number 1, and the host, who knows what's behind the doors, opens another door, say number 3, which has a goat. He says to you, "Do you want to pick door number 2?" Is it to your advantage to switch your choice of doors?

Don't answer unless you have actually thought hard about this. Even then most people won't get it. But just think of this; if it was a case of simple probability, would I have bothered to post this up?

The difference is with this one that there IS a correct answer, which can be proven. Anyway, enjoy.

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Before any door is opened theres a 1/3 chance the cars behind either door 1, 2 or 3

When door 3 is opened by presenter new chances are 0 chance of car in door 3, 1/2 chance in doors 1 and.

Seeing as your choice of door 1 was chosen before the other door was opened, you had a 1/3 chance of the car. You now know theres a 1/2 chance the car is behind door 2. So your better off changing.

Though I know that can be countered by saying the probability of door 1 having the car behind it has risen to 1/2 so it doesn't matter if you stick or change as which door the car was behind before door 3 was opened is now irrelevant.

The conclusion of which is i dont know.

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When I look into a mirror, in the image i see, my right hand is my left hand and my left hand is my right hand. But my top is still the top of me and the bottom is still the bottom of me. Why am I flipped horizontally but not vertically? :turned:

Because your eyes are placed horizontally on your body not vertically .....

The monty hall one is good ... but i cant see any other answer than no difference to your chances at all It is 50 - 50 all the way.... fact not fiction ....

how about the old classic ....

place a living cat into a steel chamber, along with a device containing a vial of hydrocyanic acid. There is, in the chamber, a very small amount of a radioactive substance. If even a single atom of the substance decays during the test period, a relay mechanism will trip a hammer, which will, in turn, break the vial and kill the cat. Come back after an hour - is the cat dead or alive ?

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Because your eyes are placed horizontally on your body not vertically .....

The monty hall one is good ... but i cant see any other answer than no difference to your chances at all It is 50 - 50 all the way.... fact not fiction ....

how about the old classic ....

place a living cat into a steel chamber, along with a device containing a vial of hydrocyanic acid. There is, in the chamber, a very small amount of a radioactive substance. If even a single atom of the substance decays during the test period, a relay mechanism will trip a hammer, which will, in turn, break the vial and kill the cat. Come back after an hour - is the cat dead or alive ?

both ;)

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Nope incorrect. (with the mathsy bit)

BEDMAS

Brackets

Exponents

Division and Multiplication

Addition and Subtraction

Only the bottom ones right (1+2x3=7) because you do the multiplication before the addition. For the top one to be right it would have to be:

(1+2)x3=9

Yeah, i knew someone would bring that up, but my points till valid.

The Monty Hall Problem

Suppose you're on a game show, and you're given the choice of three doors. Behind one door is a car, behind the others, goats. You pick a door, say number 1, and the host, who knows what's behind the doors, opens another door, say number 3, which has a goat. He says to you, "Do you want to pick door number 2?" Is it to your advantage to switch your choice of doors?

This is a good one. You have greater chance of winning the car if you change your mind, and go with the other door. It seems like you still have a 50/50 chance. But if you stick with the same door, you still have a 2/3 chance that you have a goat.

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place a living cat into a steel chamber, along with a device containing a vial of hydrocyanic acid. There is, in the chamber, a very small amount of a radioactive substance. If even a single atom of the substance decays during the test period, a relay mechanism will trip a hammer, which will, in turn, break the vial and kill the cat. Come back after an hour - is the cat dead or alive ?

Depends how long the half life of the parent atom of the radioactive substance is?

Or do i have the wrong end of the stick...

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