Punkrider Posted July 2, 2006 Report Share Posted July 2, 2006 (edited) I am making this discharger, i have completed everything except the resistor. I am trying to work out what resistor i will need. I have put my multimeter on the battery as it discharged, the relay switched off at 3.5 volts, but then after about a minute, the battery levelled out and stopped at 5.5 volts. What number number should i put into the calculation? 3.5v or 5.5v?The resistor value is calculated by using:R = Rr(Vc/Vr) - RrWhere:R is the resistor valueRr is the resistance of the relay coil (92 ohms)Vc is the cut off voltage required (5 volts) Vr is voltage at which the relay releases (3.5 or 5.5 volts)r = 92(5/3.5) - 92 = 39.43r = 92(5/5.5) - 92 = -8.4What resistor will i need, like 1/4 watt?Cheers Edited July 2, 2006 by Punkrider Quote Link to comment Share on other sites More sharing options...
ogre Posted July 2, 2006 Report Share Posted July 2, 2006 If you can wait i will print off/show this post to my ep teacher for you. he flies helicopters so will know what what do etc... Quote Link to comment Share on other sites More sharing options...
adamtrials Posted July 2, 2006 Report Share Posted July 2, 2006 If you can wait i will print off/show this post to my ep teacher for you. he flies helicopters so will know what what do etc...I fly helicopters and dont know the answer sorry... Quote Link to comment Share on other sites More sharing options...
Gavyn. Posted July 2, 2006 Report Share Posted July 2, 2006 right i'm not great at this but i'll give it ago.to calculate the power over the circuit = p(W)=I/Vso p =I(?)/Vi = current so i =v/ri =5(?)/92i =0.543a p=0.543/5=0.1086Wi think that means you need a resistor of 0.1-0.5w/40ohmfor 5.5 and 0.1-0.5w and -10 Quote Link to comment Share on other sites More sharing options...
adamtrials Posted July 2, 2006 Report Share Posted July 2, 2006 right i'm not great at this but i'll give it ago.to calculate the power over the circuit = p(W)=I/Vso p =I(?)/Vi = current so i =v/ri =5(?)/92i =0.543a p=0.543/5=0.1086Wi think that means you need a resistor of 0.1-0.5w/40ohmfor 5.5 and 0.1-0.5w and -10I x V = W i thought? Quote Link to comment Share on other sites More sharing options...
Gavyn. Posted July 2, 2006 Report Share Posted July 2, 2006 no idea it was abit of a geuss i was working on v=i x r and working the current out from the voltage and the resistance Quote Link to comment Share on other sites More sharing options...
ogre Posted July 3, 2006 Report Share Posted July 3, 2006 My ep teacher says that a 1/4 resistor will do fine Quote Link to comment Share on other sites More sharing options...
Punkrider Posted July 3, 2006 Author Report Share Posted July 3, 2006 Thanks man, much appreciated Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.