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An Rc/electrical Question


Punkrider

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I am making this discharger, i have completed everything except the resistor. I am trying to work out what resistor i will need. I have put my multimeter on the battery as it discharged, the relay switched off at 3.5 volts, but then after about a minute, the battery levelled out and stopped at 5.5 volts. What number number should i put into the calculation? 3.5v or 5.5v?

The resistor value is calculated by using:

R = Rr(Vc/Vr) - Rr

Where:

R is the resistor value

Rr is the resistance of the relay coil (92 ohms)

Vc is the cut off voltage required (5 volts)

Vr is voltage at which the relay releases (3.5 or 5.5 volts)

r = 92(5/3.5) - 92 = 39.43

r = 92(5/5.5) - 92 = -8.4

What resistor will i need, like 1/4 watt?

Cheers :geek::lol:

Edited by Punkrider
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right i'm not great at this but i'll give it ago.

to calculate the power over the circuit = p(W)=I/V

so p =I(?)/V

i = current so

i =v/r

i =5(?)/92

i =0.543a

p=0.543/5

=0.1086W

i think that means you need a resistor of 0.1-0.5w/40ohmfor 5.5 and 0.1-0.5w and -10

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right i'm not great at this but i'll give it ago.

to calculate the power over the circuit = p(W)=I/V

so p =I(?)/V

i = current so

i =v/r

i =5(?)/92

i =0.543a

p=0.543/5

=0.1086W

i think that means you need a resistor of 0.1-0.5w/40ohmfor 5.5 and 0.1-0.5w and -10

I x V = W i thought?

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