HarshRider Posted January 19, 2005 Report Share Posted January 19, 2005 hello at the moment im getting round to testing my magura booster i made for my project. i emailed magura to ask if if they could tell me the braking force of a magura hs 33 and did recive one but foolishly my email deleated it :P so if any one for some strange reason would have the braking force of the hs33 magura could they please tell me. if not i can eaisly email magura again. cheers Rich :S Quote Link to comment Share on other sites More sharing options...
Tartridge Posted January 19, 2005 Report Share Posted January 19, 2005 Depends how hard you pull it! But, something like 150N at your finger (one finger), 6:1 leverage ratio of the lever blade, then 2:1 ratio of master/slave, comes out to around 1800N. If you design your booster around a force of 2000N, thats plenty. Quote Link to comment Share on other sites More sharing options...
HarshRider Posted January 19, 2005 Author Report Share Posted January 19, 2005 cheers that should help abit :S Quote Link to comment Share on other sites More sharing options...
Will Arnold Posted January 19, 2005 Report Share Posted January 19, 2005 sorry to a pain :S but what are the sizes of cyliner in the master and slave? cheers. Quote Link to comment Share on other sites More sharing options...
Tartridge Posted January 19, 2005 Report Share Posted January 19, 2005 14mm diameter :S Quote Link to comment Share on other sites More sharing options...
Will Arnold Posted January 19, 2005 Report Share Posted January 19, 2005 cheers :S Quote Link to comment Share on other sites More sharing options...
JT! Posted January 19, 2005 Report Share Posted January 19, 2005 I thought is was 8:1 ratio. :S Quote Link to comment Share on other sites More sharing options...
FAT~DAN Posted January 19, 2005 Report Share Posted January 19, 2005 dont argue with tarty he knows EVERYTHING even im not stupid enough to argue with him Dan Quote Link to comment Share on other sites More sharing options...
Will Arnold Posted January 19, 2005 Report Share Posted January 19, 2005 Depends how hard you pull it! But, something like 150N at your finger (one finger), 6:1 leverage ratio of the lever blade, then 2:1 ratio of master/slave, comes out to around 1800N. If you design your booster around a force of 2000N, thats plenty. ← are you sure its 2:1 ratio of the master/slave? surely having two slave pistons doesent double the power?!?! :P im confuzed because tarty has always been spot on in my mind :S but now i think im right and he is wrong?!?! argh! Quote Link to comment Share on other sites More sharing options...
dave85 Posted January 19, 2005 Report Share Posted January 19, 2005 are you sure its 2:1 ratio of the master/slave? surely having two slave pistons doesent double the power?!?! :P im confuzed because tarty has always been spot on in my mind :S but now i think im right and he is wrong?!?! argh! ← Both the slaves and the master cylinder are the same size, so any force at the master piston will produce the same force on a slave piston. But there are two slaves, so the force is doubled. Quote Link to comment Share on other sites More sharing options...
fairy elephants Posted January 19, 2005 Report Share Posted January 19, 2005 Both the slaves and the master cylinder are the same size, so any force at the master piston will produce the same force on a slave piston. But there are two slaves, so the force is doubled. ← Or is the combined force of the slaves the same as the master, meaning that the force at one of the slaves is 1/2?? I dont no, just suggesting it because im bored realy :S Quote Link to comment Share on other sites More sharing options...
nb88 Posted January 20, 2005 Report Share Posted January 20, 2005 Yeah both the master and slaves are 14mm. I think the hs11s had a 16mm master or something? meaning less power....and they improved it. So its a 2:1 ratio. Quote Link to comment Share on other sites More sharing options...
Tartridge Posted January 20, 2005 Report Share Posted January 20, 2005 Or is the combined force of the slaves the same as the master, meaning that the force at one of the slaves is 1/2?? ← Nope :S Quote Link to comment Share on other sites More sharing options...
JT! Posted January 20, 2005 Report Share Posted January 20, 2005 So could maggies be made more powerful, just by changing the ratios? :S Quote Link to comment Share on other sites More sharing options...
Mark W Posted January 20, 2005 Report Share Posted January 20, 2005 It's all a matter of juggling the ratios, basically. Changing the size of the pistons and so on. However, you've got to take into acount the strength of the seals, 'cos if it's too powerful you're more likely to blow a seal (lol... just remembered a joke about a penguin blowing a seal... *sigh*). Quote Link to comment Share on other sites More sharing options...
Tartridge Posted January 20, 2005 Report Share Posted January 20, 2005 So could maggies be made more powerful, just by changing the ratios? :S ← Yes. Thats what RB levers do. Makes your frame flex more though... Quote Link to comment Share on other sites More sharing options...
JT! Posted January 20, 2005 Report Share Posted January 20, 2005 Yes. Thats what RB levers do. Makes your frame flex more though... ← Ah, but then the blocks would move less :S . I think magura got them about right. Quote Link to comment Share on other sites More sharing options...
Mark W Posted January 20, 2005 Report Share Posted January 20, 2005 How'd you work out they'd move less? They'd move more for the same amount of movement if the ratio was "better" (i.e. gave more power)? Quote Link to comment Share on other sites More sharing options...
Tartridge Posted January 20, 2005 Report Share Posted January 20, 2005 They'd move more for the same amount of movement if the ratio was "better" (i.e. gave more power)? ← Nope... JTs right... The lever displaces less fluid, so therefore moves the pads less far. Quote Link to comment Share on other sites More sharing options...
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