Thebigjam101 Posted June 30, 2014 Report Share Posted June 30, 2014 If D= gap to front distance in feet, and R= number of repetitions of gaps to front per day since March, and T is time.. When D averages at 5 feet and R averages at about 20, the equation looks like this: 5D+20R=T If T equals time in days, what number of days will it be before the forks snap? Quote Link to comment Share on other sites More sharing options...
dngr2self Posted June 30, 2014 Report Share Posted June 30, 2014 S Quote Link to comment Share on other sites More sharing options...
Thebigjam101 Posted June 30, 2014 Author Report Share Posted June 30, 2014 S "S" for soon? Quote Link to comment Share on other sites More sharing options...
AdamR28 Posted June 30, 2014 Report Share Posted June 30, 2014 Too many other variables. 1 Quote Link to comment Share on other sites More sharing options...
jack dickinson Posted June 30, 2014 Report Share Posted June 30, 2014 My echo sl forks didnt break for almost a year and theu were second hand. I did gap to fronts. Up to fronts. Hooks (not many though) and yet the forks were fine. But as soon as i did a few drop to two wheel they shot off into the distance Quote Link to comment Share on other sites More sharing options...
fruitbat Posted July 1, 2014 Report Share Posted July 1, 2014 I think you need to add a variable for user weight as this could affect the outcome of T, but on the basis of average user weight, with an accurary of 3.52% over or above, by my caculations the result is -65.2, you're forks are living on borrowed time. Quote Link to comment Share on other sites More sharing options...
Jake. Posted July 1, 2014 Report Share Posted July 1, 2014 Is this a joke? Quote Link to comment Share on other sites More sharing options...
J.KYDD Posted July 1, 2014 Report Share Posted July 1, 2014 Its gotta be, but then the OP is the current 'shit new topic' starter Quote Link to comment Share on other sites More sharing options...
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