Jump to content

Math Help


Robwalker

Recommended Posts

Just drawing up another MSPaint image haha, 2 secs :)

Edit, ok.

Yeah, your formula is spot on, here's the working/explanation:

Ok, starting hanging down as required this time!

anglel.jpg

We know that we can split up the 2m start rod into 2*cos(theta) + 0.027

(Is that clear from the image, if not shout)

So, we know that 2*cos(theta) = 2 - 0.027

as such, cos(theta) = (2-0.027)/2

so theta = arccos((2-0.027)/2)

=0.165 rad or around 9.425 degrees

:)

I think that's about right, though I'm in the middle of 2 other bits of coursework/coding so I may very well not be thinking straight :P

  • Like 1
Link to comment
Share on other sites

Never heard the full version before. Extremely frustrating just to listen to. It's unbelievable that out of all the people he spoke to non of them seemed understand basic maths.

Link to comment
Share on other sites

  • 3 weeks later...

Yo so its 10, 11 and 12 im stuck on. Any help.please !! pulling ny teeth out :(

Without knowing what you've done on the course/expected to know I'm going to assume you've covered some basic differentiation? (Since that's what 10/11 seem to want you to do)

10 is just a bit of differentiation. Once gives you stationary points and twice tells you about the nature of them. Though from plotting the curve (or just visualising it since it's a relatively straightforward x^3 type) you should be able to get a pretty good idea of things.

11. Again, differentiating gives you velocity. From here you should be able to find the value of t for v(t) = 0 and work out the other parts (acc. = dv/dt as usual)

12. Will write up some shiz and get in here to try and explain it after food (Y)

Edit; f**k it, I've got a minute while things are cooking. This should get you going ;)

mathdann.png

From there, you've got a function in x much like in Q10. Find the maximum of this function for the final part of the question (Y)

Link to comment
Share on other sites

  • 4 weeks later...

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
  • Recently Browsing   0 members

    • No registered users viewing this page.
×
×
  • Create New...