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Physics Question


MikeCottTrials

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Hey guys, as always I think this forum could be a life line for me...

A car is initially at 18km per hour and travels at this velocity for 44 seconds; it then accelerates to 45 km per hour in 30 seconds and stays at this velocity for 56 seconds. What is the total distance covered by the car in the 130 seconds described?

This is how I've calculated it...

18000/60/60=5, 5*44=220

45-18=27, 30/27=0.9, 1/2 (5+12.5)*30=262.5

45000/60/60=12.5, 12.5*56=700

220+262.5+700=1182.5

Answer: 1.18km

Just looking for some reassuring, you are correct sir... or you are wrong and here is why B)

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The first and last bits are easy. Second bit you need to use s= ½(u+v)t which I think you've got.

The extra working out you did (45-18=27, 30/27=0.9*) works out the acceleration (although you've done it kph/s which is likely to confuse matters) and isn't really necessary - it just adds another step. You could however calculate the acceleration in m/s/s and then substitute that into s= ut+ ½at² to give you the distance over the middle part of the journey (262.5m).

*30/27 doesn't equal 0.9 :P

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