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Trigonometric Identies


PaRtZ

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Firstly I f*cking hate these things. biggest waste of time ever! :angry:

Got to prove 1 + cot2x = cosec2x

Got NO idea how to do. Just spent the last hour substituting what I know in and nothing turns out right. The more explained, the better

thanks

Edited by PaRtZ
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Using the identity 1 + cot2x = cosec2x you can replace it with cosec2x.

Giving you cosec2x = cosec2x.

I left my bag at college but thats all i remember.

Matt

yeah the question is, prove it :P I think benjaminge has posted in daves spin off thread...

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Firstly I f*cking hate these things. biggest waste of time ever! :angry:

Got to prove 1 + cot2x = cosec2x

Got NO idea how to do. Just spent the last hour substituting what I know in and nothing turns out right. The more explained, the better

thanks

What are the other functions? You need to either split cosec2x into seperate parts by proving that its made up of something else. like saying 2x+y=3 and as a seperate rule you know y=x2 so you substitue that in instead of y.

You could also bring the cot over and divide cosec by cot, then follow it through splitting it up into sin/cos/tan and finding where it is on the corresponding graph maybe?

Been a while since i did maths at this level :lol:

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This make any sense?

Its just the last step, how do you get the sin2x cos2x ? All I can gather is you added together 1 / sin2x and cos2x / sin2x In which case I need to re-learn how to cross multiply again :(

Answer me that and im sorted and thanks alot everyone else :)

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The last step is just multiplying both sides by sin2x. The "1" then becomes sin2x and the cos2x/sin2x cancels leaving just cos2x. On the other side you'd have sin2x/sin2x which cancels to 1.

foooking lovely!!!!!

Thank you soo much!

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No problem, Mink did the hard work :) I remember doing this stuff a few years back but without my book of trig identities (which is sat in a box somewhere along with all my other college and uni work!) I wouldn't have been able to do it these days.

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